-10y+18=-15y^2+26y

Solution for -10y+18=-15y^2+26y equation:

-10y+18=-15y^2+26y

We move all terms to the left:

-10y+18-(-15y^2+26y)=0

We get rid of parentheses

15y^2-26y-10y+18=0

We add all the numbers together, and all the variables

15y^2-36y+18=0

a = 15; b = -36; c = +18;
Δ = b2-4ac
Δ = -362-4·15·18
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-6\sqrt{6}}{2*15}=\frac{36-6\sqrt{6}}{30}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+6\sqrt{6}}{2*15}=\frac{36+6\sqrt{6}}{30}
$